Pascal's triangle

import numpy as np
from scipy.special import binom

nmax = 8
for n in range(nmax+1):
    fmt = ' {:^3d}'*(n+1)
    pascal_row = fmt.format(*np.array(binom(n,np.arange(n+1)), dtype='i4'))
    print('{:^40s}'.format(pascal_row))

The $n$th row of Pascal's triangle contains $n$ numbers, each of which is formatted in a field width of three characters; the entire row is then centered in a total field size of 40 characters.

Output:

                1                   
              1   1                 
            1   2   1               
          1   3   3   1             
        1   4   6   4   1           
      1   5  10  10   5   1         
    1   6  15  20  15   6   1       
  1   7  21  35  35  21   7   1     
1   8  28  56  70  56  28   8   1

Pascal's triangle

Solution P8.1.1