Sorting one list based on items in another

Question Q2.4.7

Sorting a list of tuples arranges them in order of the first element in each tuple first. If two or more tuples have the same first element, they are ordered by the second element, and so on:

>>> sorted([(3,1), (1,4), (3,0), (2, 2), (1, -1)])
[(1, -1), (1, 4), (2, 2), (3, 0), (3, 1)]

This suggests a way of using zip to sort one list using the elements of another. Implement this method on the data below to produce an ordered list of the average amount of sunshine in hours in London by month. Output the sunniest month first.

JanFebMarAprMayJunJulAugSepOctNovDec
44.765.4101.7148.3170.9171.4176.7186.1133.9105.459.645.8

Solution