any(x) and not all(x) is True if at least one item in x is equivalent to True but not all of them:

>>> x1, x2, x3 = [False, False], [1, 2, 3, 4], [1, 2, 3, 0]
>>> any(x1) and not all(x1)
False
>>> any(x2) and not all(x2)
False
>>> any(x3) and not all(x3)
True